今天就是讲给REMOTE_ADDR不可以伪造的，就在curl 中也无法伪造 相对是比较安全的服务端ip获取方法，当然，也有可能被路由伪造 这个不好说，因为REMOTE_ADDR 是底层的回话ip地址，路由是可以发起伪造。所以，网上很多人都在问这个问题，也有很多人不死心，但现实确实是残酷的 也是完美的给个演示案例你吧：你就信了1.将以下代码保存为 Client.php //php脚本开始
<?php
$ch = curl_init();
$url = "http://localhost/ser.php";
$header = array( 'CLIENT-IP:208.165.188.175', 'X-FORWARDED-FOR:208.165.188.175, );
//声明伪造head请求头
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HTTPHEADER, $header);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,true);
$page_content = curl_exec($ch); curl_close($ch);
echo $page_content;?>2.将以下文件保存为ser.php//php脚本开始
<?php
echo getenv('HTTP_CLIENT_IP');
echo getenv('HTTP_X_FORWARDED_FOR');
echo getenv('REMOTE_ADDR');
?>3.运行结果//html脚本开始
208.165.188.175
208.165.188.175
127.0.0.1
//上面结果可看出,http_client_ip,http_x_forwarded_for 都被伪造了
而remote_addr 还是127.0.0.1 就是客户端ip4.附上一个PHP获取IP地址函数function get_real_ip($type = 0,$adv=false) {
$type = $type ? 1 : 0;
static $ip = NULL;
if ($ip !== NULL) return $ip[$type];
if($adv){
if (isset($_SERVER['HTTP_X_FORWARDED_FOR'])) {
$arr = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
$pos = array_search('unknown',$arr);
if(false !== $pos) unset($arr[$pos]);
$ip = trim($arr[0]);
}elseif (isset($_SERVER['HTTP_CLIENT_IP'])) {
$ip = $_SERVER['HTTP_CLIENT_IP'];
}elseif (isset($_SERVER['REMOTE_ADDR'])) {
$ip = $_SERVER['REMOTE_ADDR'];
}
}elseif (isset($_SERVER['REMOTE_ADDR'])) {
$ip = $_SERVER['REMOTE_ADDR'];
}
// IP地址合法验证
$long = sprintf("%u",ip2long($ip));
$ip = $long ? array($ip, $long) : array('0.0.0.0', 0);
return $ip[$type];
}
